4q^2+44q+121=0

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Solution for 4q^2+44q+121=0 equation: 



4q^2+44q+121=0

a = 4; b = 44; c = +121;
Δ = b2-4ac
Δ = 442-4·4·121
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$q=\frac{-b}{2a}=\frac{-44}{8}=-5+1/2$

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